حل التمرين

[eces2007]

بسم الله الرحمان الرحيم

اريد منكم حل التمرين 3 من فضلكم
[IMG][/IMG]
وشكرا

[Lvka the end]

حل التمرين 03 :

/ 1/

MO.MA= ?

MA(2-x ; -y ) MO( -x ; -y )

MO.MA =(2-x)(-x)+(-y)(-y)=x²+y²-2x

2/

MA.MO=3 ====è x²+y²-2x=3 ===è MO.MA= x²+y²-2x-3=0

I(1 ;0) r=2 =è T=a²+b²-4c /4 è T= (-2)²+(0)²-4(-3)/4=16/4=4

T>0 ==è I(-a/2 ; -b/2) I(2/2 ;0/2) I(1 ; 0)

R =jider T ya3ni jider 4= 2

W howa elmatloub

2/

B(0 ;jider3)

( c) =x²+y²-2x-3=0 =è no3awed i7dathiyat B fi el mo3adalanajid=è0²+(jider3)²-2(0)-3=0

0+3-3=0

0=0 w minhou B tantami li da2ira (c )

3/

Mo3adalatmostakim (D) :

IA howa cho3a3 nadimi lil mostakim ( D) w minhou :IA(a ;b )==è IA(1 ;0)

(D) : 1x+0y+c=0 ==è (D) :x+c=0 ==è bima ana A tantami ila (D) tosbi7

A(2 ;0) ===è (D) : 2+c=0 ===è c=-2 è(D) :x-2=0

Mo3adalatalmamas (T) :

(T) yo3amid(AB) 7ayto (AB) howa koter al da2ira (C) =è AB(0-2 ;jider3 -0 ) è AB(-2 ; jider3 )

(T) :-2x+jider3y+c=0 =è bima ana B tantami ila (T) è (T) : -2(0)+jider3(jider3)+c=0

(T) :3+c=0 =è c=-3 =è (T) :-2x+jider3y-3=0

4/

Ta3yin i7dathiyat E noktat takato3 (D) w (T)

(x-2=0…………………….1)*(-2)

-2x+jider3y-3=0…………..2

-2x+4=0………..1

-2x+jider3y-3=0……….2

Bi jame3 1+2tosbe7

Jider3y+1=0

Jider3y=-1

Y=-1/jider3 y=-jider3/3

No3awed kimaty fi 3ibara rakem 2 najid

X=-2 wa minhou E( -2 ; -jider3/3 )

5/

*El masssafabayna (D) wa E :

Bitatbik elkanon najid el masafa = 4

*el massafabayna (T) wa E :

Nafes kanonnajid massafa =0

6/ el rassemsahel : 1/ narsom ma3lam 2/ no3ayem nikat A B I 3/norsem da2ira (C )

5/ narsommamas (T) w mostakin (D)

[قلب الاسد1]

nnnnnnnnnnnnnnnnnnnnnn