(لمحترفي لغة السي++) aide moi svp segmentation d'un document texte

[صفوان مازيغ]

اعينوني من فضلكم...

[صفوان مازيغ]

nothing special...

[صفوان مازيغ]

pfffffffffffffffffffffffffffffffffffff

[Abe_Sparrow]

استخدم المكتبة القياسية C++ Standard Library ستجد بها كل ما تحتاجه.

[صفوان مازيغ]

.................................

[you92cef]

c'est bien d'utiliser flex and yacc sous unix pour faire une analyse lexicale

une programe qui fait l'analyse lexicale SQL

#include<stdio.h>
#include<conio.h>
#include<ctype.h>
#include<string.h>
char *mc[10]={"create","select","insert","into","from","all","table","values","where","sum"};
char *sep[10]={" ","(",")",",",":",";","."};
char *op[20]={"=","<",">","!=","==",">=","<=","+","-","/","*"};
char *id[30];
char *num[30];
char f[40];
int ismc(char* a)//recherche des mots clé 
{
 int i=0;
 while (mc[i]!=NULL)
    {
      if(strcmp(mc[i],a)) i++;
      else return 1;
      }
  return  0;
 }    
int issep(char* a)//recherche des separateurs
{
 int i=0;
 while (sep[i]!=NULL)
    {
      if(strcmp(sep[i],a)) i++;
      else return 1;
      }
  return  0;
 } 
int isop(char *a)//recherche des operateurs
{
 int i=0;
 while (op[i]!=NULL)
    {
    if(strcmp(op[i],a)) i++;
      else return 1;
      }
 return  0;
 }

int main(void)
{ 
    
    int jj=0;
    printf("entrer une chaine:");
    char p[100];
    gets(p);
     char l[2];char m[2];
    int i=0;int k=0;
    int j=0,cpt=0,d,a,b;
    while (p[i]!='\0') 
      {
      
        l[0]=p[i];l[1]='\0';      
        if(isalnum(p[i])) d=1;
        else d=0;
         a=issep(l);b=isop(l);
                  

            switch(d)
          {
          case 0:
           
          if(issep(l)) {i++;}
                        else if(isop(l)){  
                                                    m[0]=p[i+1];
                                                    m[1]='\0';
                                                    if (issep(m)|| isalnum(p[i+1]))   {printf("\noperateur:'%s'\n",l); i++; }
                                                       else {if(isop(strncat(l,m,1))&&(m[0]!='\0')) {printf("\noperateur:'%s'\n",l);i++;i++;}
                                                                else {l[1]='\0';printf("\noperateur:'%s'\n",l);i++;}}}
                                else { 
                                                    m[0]=p[i+1];
                                                    m[1]='\0';
                                                     if(isop(strncat(l,m,1))&&(m[0]!='\0')) {printf("\noperateur:'%s'\n",l);i++;i++;}
                                                                else {l[1]='\0';printf("\nerror lexiqal: operateur inconnu '%s' \n",l);i++;}}
                                                                
                                                                                                         break;
                                          
                                                      
           case 1: 
           jj=0;
           while(isalnum(p[i]))
                          {  
                                         
                                              while(isdigit(p[i]))
                                                { 
                                                 
                                                 f[jj]=p[i];
                                                 f[jj+1]='\0';
                                                 i++;
                                                 jj++;
                                                }
                                             
                                              if(jj) { num[k]=f;
                                                                 printf("\nnombre[%d]:%s\n",k,num[k]);
                                                                 k=k+1;
                                                                 break;
                                                                 
                                                                }
                                                                
                                            
                                            while(isalnum(p[i]))
                                             {
                                               f[jj]=p[i];
                                                 f[jj+1]='\0';
                                                 jj++;
                                               i++;
                                             }
                                            
                                               if(ismc(f)==0){
                                               id[j]=f;
                                               printf("\nidentificateur[%d]:%s\n",j,id[j]);
                                               j=j++;}
                                               else printf("\nmot cle:%s\n",f);
                                            }
                                           
                                            
                      
                                                           
           }
   
      }


    
      
getch();    
}

[FATH]

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