[slimanimaths]

[]On a x^2 ln⁡((x+1)/x)-x+1/2= x^2 ln⁡〖(((x+1)/x)/e^x )+1/2 〗 On a x^2⟶+∞ et (((x+1)/x)/e^x )⟶0 donc ln⁡〖(((x+1)/x)/e^x )→-∞ 〗 Et alors x^2 ln⁡〖(((x+1)/x)/e^x )+1/2 〗→-∞ Lim f(x) = -∞