المساعد الشخصي الرقمي

مشاهدة النسخة كاملة : أول طلب لي في منتدى الجلفة خاص بالفيزياء وأتمنى دخول أساتذة الفيزياء


naroutouzidan
2013-05-15, 18:23
أرجووووووووووووووكم أريد الاجابة النموذجية لهذا الموضوع هذه صورة للموضوع لأنه لم ينسخ الرسومات
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صحيح أو خطأ مع التعليل:
ü طيف الضوء الصادر من جسم ساخن هو طيف يتسع نحو اللون الأحمر بزيادة درجة الحرارة.
ü شعاع ضوئي يجتاز موشور من الزجاج زاويته A=60° و قرينة انكساره n=1.62 ل يبرز من الموشور.
ü ليزر طبي يصدر إشعاعا طول موجته λ=10.6 μ m ينتمي الى المجال تحت الأحمر( IR )
التمرين الثاني
زجاج من نوع Flintبتميز بقرينة انكسار قيمتها :
nR=1.612من أجل إشعاع احمر
nJ=1.621 من أجل إشعاع أصفر زجاج هواء
nB=1.671 من أجل إشعاع أزق
1) ما هي سرعة كل إشعاع عند اجتيازه هذا الزجاج ؟
2) تسقط حزمة ضوئية على سطح الزجاج بزاوية ورود 61.5°
_احسب زاوية انكسار كل شعاع
_ارسم الإشعاعات المنكسرة بدقة
_احسب زاوية انحراف كل شعاع.ماذا تلاحظ؟
_ارسم و حدد بالتقريب اتجاه الشعاع الأخضر
التمرين الثالث
ABCD مربع طول ضلعه a=2 cm توضع في رؤوسه الشحنات qD , qc , qB , qA, . A B
1_مثل القوى المتبادلة بين qA و بقية الشحنات.
2_احسب قيمة القوة الناتجة عن تأثير الشحنات qB , qAqD , في الشحنة , qc
اذا =10-6c/2qD =qc =qB =qA
D C
التمرين الرابع
1) نفاعل حجم V(L) من غاز ثنائي الأكسيجين O2لاحتراق 6.35 g من معدن النحاسCu
فيتشكل مسحوق اسود من أكسيد النحاس CuO.
_أكتب معادلة التفاعل الحادث
_أنشئ جدول تقدم التفاعل
_ارسم المنحنى البياني nCu=f(x)
2)إذا علمت أن من أجل x=0.005 mole يكون حجم ثنائي الأكسيجين المتبقي 0.12L :
_احسب حجم الغاز O2 الابتدائي
_استنتج المتفاعل المحد
_أعط الحصيلة النهائية للتفاعل Cu=63.5 g/mole Vm=24 L/mole
التمرين الخامس
كلور الكالسيوم Ca Cl2 ينحل في الماء معطيا شوارد الكلور Cl- و شوارد الكالسيوم Ca2+ .نذيب كتلة m منه في
1L من الماء و نأخذ100 mL فنجد كمية مادة لشوارد الكلور nCl-=0.02 mole :
1)أكتب معدلة انحلال كلور الكالسيوم في الماء
2)ما هو التركيز المولي للمحلول بشوارد Cl- وCa2+
3)ما هو التركيز المولي للمحلول C ؟استنتج الكتلة m لكلور الكالسيوم المذابة في الماء .
Ca=40 g/mole Cl=35.5 g/mole

soulami sousou
2013-05-15, 18:27
حل تمرين الاول http://im31.gulfup.com/Jiat7.jpg

maneloutaki
2013-05-15, 18:30
اسفة جداااااااااااااا

naroutouzidan
2013-05-15, 18:35
شكرا أختي ولكن ليس هو حل للتمرين الاول

soulami sousou
2013-05-15, 18:49
شكرا أختي ولكن ليس هو حل للتمرين الاول

انا اقصد ان تساعدوني في حل تمرين الاول غدا عندي اختبار وراني حاصلة

naroutouzidan
2013-05-15, 19:02
راه عندي الحل نتاع التمرينين نتاعك في زوج دوك نحوس عليهم ونرسلهم لك ممكن نطول عليك شويا

soulami sousou
2013-05-15, 19:22
راه عندي الحل نتاع التمرينين نتاعك في زوج دوك نحوس عليهم ونرسلهم لك ممكن نطول عليك شويا

ربي يفتح عليك راني نستني خلاص راني دا نهبل كرهت هبطل كامل المورال كيما عرفتش نحلهم

naroutouzidan
2013-05-15, 20:45
حساب شدة القوة الكهربائية التي تؤثر بها q1على q2 :
F= k.(q1)(q1) = 9.109.2.10-6.3.10-6 = 0.00216
(D²) 25
حساب شدة القوة الكهربائية التي تؤثر بها q3على q2 :
حساب المسافة من q2 إلى q3 :
Tan 27 = 0.5

Tan q3 = طول المقابل = 0.5
طول المجاور

طول المجاور = 5/0.5 = 10
حساب الشدة :
F= k.(q1)(q1) = 9.109.4.10-6.3.10-6 = 0.00108
(D²) 100

naroutouzidan
2013-05-15, 20:47
حساب شدتها :
file:///C:\Users\naroutou\AppData\Local\Temp\msohtmlclip1\ 01\clip_image001.gifF22 = F 12/2 + F32/2 = 0.002162 + 0.001082 = 0.000005832
F2= 0.000005832 = 0.00241
يجب أن تكون q2 تساوي 39.99
0.002162 + x = 1600
X2 = 1600-0.002162 = 1599.99
X = 39.99

naroutouzidan
2013-05-15, 20:48
الشكل لم أستطع رفع إعذريني
وهذا حلي وليس حل من كتاب لأنني لم أجد الحل

ْفاطمــــ الزهراء ــــة
2013-05-15, 20:56
ساعدونيhttp://www.djelfa.info/vb/showthread.php?t=1296894