áãÏÇ áÇ ÊÓÇÚÏæäí.............. - ãäÊÏíÇÊ ÇáÌáÝÉ áßá ÇáÌÒÇÆÑííä æ ÇáÚÑÈ

ÇáÚæÏÉ   ãäÊÏíÇÊ ÇáÌáÝÉ áßá ÇáÌÒÇÆÑííä æ ÇáÚÑÈ > ãäÊÏíÇÊ ÇáÊÚáíã ÇáËÇäæí > ãäÊÏì ÇáÓäÉ ÇáËÇäíÉ ËÇäæí 2AS > ÞÓã ÇáÇÓÊÝÓÇÑÇÊ æ ØáÈÇÊ ÇáÃÚÖÇÁ

Ýí ÍÇá æÌæÏ Ãí ãæÇÖíÚ Ãæ ÑÏæÏ ãõÎÇáÝÉ ãä ÞÈá ÇáÃÚÖÇÁ¡ íõÑÌì ÇáÅÈáÇÛ ÚäåÇ ÝæÑðÇ ÈÇÓÊÎÏÇã ÃíÞæäÉ ÊÞÑíÑ Úä ãÔÇÑßÉ ÓíÆÉ ( ÊÞÑíÑ Úä ãÔÇÑßÉ ÓíÆÉ )¡ æ ÇáãæÌæÏÉ ÃÓÝá ßá ãÔÇÑßÉ .

ÂÎÑ ÇáãæÇÖíÚ

áãÏÇ áÇ ÊÓÇÚÏæäí..............

ãæÖæÚ ãÛáÞ
 
ÃÏæÇÊ ÇáãæÖæÚ ÇäæÇÚ ÚÑÖ ÇáãæÖæÚ
ÞÏíã 2014-02-08, 11:22   ÑÞã ÇáãÔÇÑßÉ : 1
ãÚáæãÇÊ ÇáÚÖæ
NADIR22
ÚÖæ ãÔÇÑß
 
ÇáÕæÑÉ ÇáÑãÒíÉ NADIR22
 

 

 
ÅÍÕÇÆíÉ ÇáÚÖæ










456ty Êã ÊÑÔíÍ ÅÌÇÈÉ ãÝÖáÉ áãÏÇ áÇ ÊÓÇÚÏæäí..............


ãä ÝÖáßã ÇÍÊÇÌ Íá åÏå ÇáÊãÇÑíä
72Õ172
88Õ173
27Õ168









 


ÃÝÖá ÌæÇÈ - ßÊÈå Nouna-31
ÇáÓáÇã Úáíßã æ ÑÍãÉ Çááå

ÇÎí ÇáßÑíã ÚäÏí Íáæá ÇáÊãÇÑíä áä ÇÈÎá Úáíß Èåã áßä ÇáØÑíÞÉ Úáì ÑÈí

ÊãÑíä 72 : 1/ U(2) =7 / U(3) =10 / U(4) = 13 / U(5) = 16
2/ U(n+2) - U(n+1) = U(n+1) - U(n) = U(1) - U(0) = 3 / q = 3
3/ U(n) = 3n+1
4/ U(n) = 361 ãÚäÇå 120= n
5/ S = 6n² - n

ÊãÑíä 88 : 1/ V(n+1) = U(n+1) / n+1 = 3/4 Vn / V1= 3/4 / r = 3/4
2/ (V(n) = (3/4) Ouss (n) / V(n+1) - V(n) = -1/4(3/4) Ouss (n)æ ãäå (Vn) ãÊäÇÞÕÉ ÊãÇãÇ
4/ U(n+1) - U(n) = n(3/4) Ouss (n) -n+3/4n æãäå ÇÈÊÏÇÁ ãä ÇáÑÊÈÉ n0 = 3 Êßæä (U(n ãÊäÇÞÕÉ ÊãÇãÇ

ÊãÑíä 27 : 1/ U0 = -5 / U1 = - 2 / U2 = 5 / U3 = 10
2/ U0= -1 / U1 = 6 / U2 = 12 / U3 = 12.5
3/ U0 = 6 / U1 = 10.5 / U2 = 5 / U3 = 6

ÇÑÌæ Çä íßä ãÇ ßÊÈÊå ãÝåæã æ ÇÊãäì Çä íÝíÏß
ÞÏíã 2014-02-08, 13:13   ÑÞã ÇáãÔÇÑßÉ : 2
ãÚáæãÇÊ ÇáÚÖæ
Nouna-31
ÚÖæ ÌÏíÏ
 
ÇáÕæÑÉ ÇáÑãÒíÉ Nouna-31
 

 

 
ÅÍÕÇÆíÉ ÇáÚÖæ










ÇÝÊÑÇÖí

ÇáÓáÇã Úáíßã æ ÑÍãÉ Çááå

ÇÎí ÇáßÑíã ÚäÏí Íáæá ÇáÊãÇÑíä áä ÇÈÎá Úáíß Èåã áßä ÇáØÑíÞÉ Úáì ÑÈí

ÊãÑíä 72 : 1/ U(2) =7 / U(3) =10 / U(4) = 13 / U(5) = 16
2/ U(n+2) - U(n+1) = U(n+1) - U(n) = U(1) - U(0) = 3 / q = 3
3/ U(n) = 3n+1
4/ U(n) = 361 ãÚäÇå 120= n
5/ S = 6n² - n

ÊãÑíä 88 : 1/ V(n+1) = U(n+1) / n+1 = 3/4 Vn / V1= 3/4 / r = 3/4
2/ (V(n) = (3/4) Ouss (n) / V(n+1) - V(n) = -1/4(3/4) Ouss (n)æ ãäå (Vn) ãÊäÇÞÕÉ ÊãÇãÇ
4/ U(n+1) - U(n) = n(3/4) Ouss (n) -n+3/4n æãäå ÇÈÊÏÇÁ ãä ÇáÑÊÈÉ n0 = 3 Êßæä (U(n ãÊäÇÞÕÉ ÊãÇãÇ

ÊãÑíä 27 : 1/ U0 = -5 / U1 = - 2 / U2 = 5 / U3 = 10
2/ U0= -1 / U1 = 6 / U2 = 12 / U3 = 12.5
3/ U0 = 6 / U1 = 10.5 / U2 = 5 / U3 = 6

ÇÑÌæ Çä íßä ãÇ ßÊÈÊå ãÝåæã æ ÇÊãäì Çä íÝíÏß










ÞÏíã 2014-02-10, 17:19   ÑÞã ÇáãÔÇÑßÉ : 3
ãÚáæãÇÊ ÇáÚÖæ
NADIR22
ÚÖæ ãÔÇÑß
 
ÇáÕæÑÉ ÇáÑãÒíÉ NADIR22
 

 

 
ÅÍÕÇÆíÉ ÇáÚÖæ










ÇÝÊÑÇÖí

ÔßÑÇ ÌÒíáÇ ÇÎÊÇå










ãæÖæÚ ãÛáÞ

ÇáßáãÇÊ ÇáÏáÇáíÉ (Tags)
ÂáíÇ, ÊÓÇÚÏæäí..............


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