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Ýí ÍÇá æÌæÏ Ãí ãæÇÖíÚ Ãæ ÑÏæÏ ãõÎÇáÝÉ ãä ÞÈá ÇáÃÚÖÇÁ¡ íõÑÌì ÇáÅÈáÇÛ ÚäåÇ ÝæÑðÇ ÈÇÓÊÎÏÇã ÃíÞæäÉ ( ÊÞÑíÑ Úä ãÔÇÑßÉ ÓíÆÉ )¡ æ ÇáãæÌæÏÉ ÃÓÝá ßá ãÔÇÑßÉ .
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2014-02-08, 11:22 | ÑÞã ÇáãÔÇÑßÉ : 1 | ||||
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ÃÝÖá ÌæÇÈ - ßÊÈå Nouna-31 |
ÇáÓáÇã Úáíßã æ ÑÍãÉ Çááå ÇÎí ÇáßÑíã ÚäÏí Íáæá ÇáÊãÇÑíä áä ÇÈÎá Úáíß Èåã áßä ÇáØÑíÞÉ Úáì ÑÈí ÊãÑíä 72 : 1/ U(2) =7 / U(3) =10 / U(4) = 13 / U(5) = 16 2/ U(n+2) - U(n+1) = U(n+1) - U(n) = U(1) - U(0) = 3 / q = 3 3/ U(n) = 3n+1 4/ U(n) = 361 ãÚäÇå 120= n 5/ S = 6n² - n ÊãÑíä 88 : 1/ V(n+1) = U(n+1) / n+1 = 3/4 Vn / V1= 3/4 / r = 3/4 2/ (V(n) = (3/4) Ouss (n) / V(n+1) - V(n) = -1/4(3/4) Ouss (n)æ ãäå (Vn) ãÊäÇÞÕÉ ÊãÇãÇ 4/ U(n+1) - U(n) = n(3/4) Ouss (n) -n+3/4n æãäå ÇÈÊÏÇÁ ãä ÇáÑÊÈÉ n0 = 3 Êßæä (U(n ãÊäÇÞÕÉ ÊãÇãÇ ÊãÑíä 27 : 1/ U0 = -5 / U1 = - 2 / U2 = 5 / U3 = 10 2/ U0= -1 / U1 = 6 / U2 = 12 / U3 = 12.5 3/ U0 = 6 / U1 = 10.5 / U2 = 5 / U3 = 6 ÇÑÌæ Çä íßä ãÇ ßÊÈÊå ãÝåæã æ ÇÊãäì Çä íÝíÏß |
2014-02-08, 13:13 | ÑÞã ÇáãÔÇÑßÉ : 2 | |||
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ÇáÓáÇã Úáíßã æ ÑÍãÉ Çááå |
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2014-02-10, 17:19 | ÑÞã ÇáãÔÇÑßÉ : 3 | |||
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ÇáßáãÇÊ ÇáÏáÇáíÉ (Tags) |
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ÇáãÔÇÑßÇÊ ÇáãäÔæÑÉ ÊÚÈÑ Úä æÌåÉ äÙÑ ÕÇÍÈåÇ ÝÞØ¡ æáÇ ÊõÚÈøÑ ÈÃí Ôßá ãä ÇáÃÔßÇá Úä æÌåÉ äÙÑ ÅÏÇÑÉ ÇáãäÊÏì
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